Two-sample t test for difference of means | AP Statistics

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In this lesson, Kaito conducts a two-sample T-test to determine if there is a significant difference in the heights of tomato plants between two fields. By setting up null and alternative hypotheses, ensuring the validity of the test through specific assumptions, and calculating the T statistic and P-value, Kaito finds that the P-value (0.048) is less than the significance level (0.05), leading to the rejection of the null hypothesis and confirming a statistically significant difference in plant heights.

Analyzing Tomato Plant Heights: A Two-Sample T-Test

Introduction

Kaito, a dedicated tomato grower, wants to find out if the heights of his tomato plants vary between two different fields. To explore this, he randomly selects a sample of plants from each field and measures their heights. This article explains how to conduct a two-sample T-test to analyze the data he collected.

Setting Up the Hypotheses

Before diving into the T-test, we need to set up our hypotheses:

Null Hypothesis (H0): There is no difference in the average heights of tomato plants between the two fields. In other words, ( mu_A = mu_B ).

Alternative Hypothesis (H1): There is a difference in the average heights of tomato plants between the two fields, expressed as ( mu_A neq mu_B ).

Assumptions for the T-Test

For the T-test to be valid, we must ensure certain conditions are met:

1. Random Condition: The samples should be randomly chosen.
2. Normal Condition: The distribution of the sample means should be approximately normal.
3. Independent Condition: The samples from each field must be independent of one another.

Assuming these conditions hold true, we proceed with the analysis using a significance level of 0.05.

Calculating the T Statistic

To perform the two-sample T-test, we calculate the T statistic using the formula:

[ T = frac{bar{X}_A – bar{X}_B}{sqrt{frac{s_A^2}{n_A} + frac{s_B^2}{n_B}}} ]

Where:
– ( bar{X}_A ) and ( bar{X}_B ) are the sample means from fields A and B, respectively.
– ( s_A ) and ( s_B ) are the sample standard deviations from fields A and B.
– ( n_A ) and ( n_B ) are the sample sizes from fields A and B.

Sample Data

Let’s assume the following sample data:
– Mean height of field A (( bar{X}_A )): 1.3 meters
– Mean height of field B (( bar{X}_B )): 1.6 meters
– Standard deviation of field A (( s_A )): 0.5 meters
– Standard deviation of field B (( s_B )): 0.3 meters
– Sample size of field A (( n_A )): 22
– Sample size of field B (( n_B )): 24

Calculation Steps

1. **Calculate the numerator**:
[ bar{X}_A – bar{X}_B = 1.3 – 1.6 = -0.3 ]

2. **Calculate the denominator**:
[ sqrt{frac{0.5^2}{22} + frac{0.3^2}{24}} = sqrt{frac{0.25}{22} + frac{0.09}{24}} approx sqrt{0.01136 + 0.00375} approx sqrt{0.01511} approx 0.123 ]

3. **Calculate the T statistic**:
[ T = frac{-0.3}{0.123} approx -2.44 ]

Determining the P-Value

To find the P-value associated with the calculated T statistic, we refer to the T distribution. Since this is a two-tailed test, we consider both tails of the distribution.

Degrees of Freedom

Using a conservative approach, the degrees of freedom (df) is calculated as:
[ df = min(n_A – 1, n_B – 1) = min(22 – 1, 24 – 1) = 21 ]

Calculating the P-Value

Using a T-distribution calculator, we find the probability of obtaining a T value as extreme as -2.44. The resulting P-value is approximately 0.024. Since this is a two-tailed test, we multiply this value by two, yielding a final P-value of approximately 0.048.

Conclusion

By comparing the P-value to the significance level of 0.05, we see that the P-value (0.048) is less than the significance level. Therefore, we reject the null hypothesis. This indicates that there is a statistically significant difference in the heights of tomato plants between the two fields, supporting Kaito’s suspicion that the sizes of his tomato plants differ.

  1. Reflecting on the article, what new insights did you gain about the process of conducting a two-sample T-test?
  2. How do the assumptions for the T-test, such as randomness and independence, influence the validity of the test results?
  3. In what ways did the article clarify the importance of setting up null and alternative hypotheses before conducting a statistical test?
  4. What challenges might arise when ensuring the normal condition is met for the T-test, and how could these be addressed?
  5. Discuss how the sample data provided in the article helped you understand the calculation of the T statistic and its significance.
  6. How does the concept of degrees of freedom impact the interpretation of the T-test results in this article?
  7. What are the implications of rejecting the null hypothesis in the context of Kaito’s tomato plant study?
  8. How might the findings from this article influence your approach to analyzing data in your own field of interest?
  1. Conduct a Mock T-Test

    Gather your classmates and split into two groups. Each group will represent one of Kaito’s fields. Measure a characteristic (e.g., height) of a common object, like books or water bottles, and perform a two-sample T-test using the data. Discuss your findings and compare them to the article’s results.

  2. Create a Hypothesis Poster

    Design a poster that visually represents the null and alternative hypotheses discussed in the article. Use diagrams and examples to illustrate the concept of hypothesis testing. Present your poster to the class and explain the significance of each hypothesis.

  3. Simulate Data Analysis

    Use statistical software or a programming language like R or Python to simulate the data analysis process described in the article. Input the sample data provided, calculate the T statistic, and determine the P-value. Share your code and results with your peers.

  4. Debate the Assumptions

    Organize a debate on the assumptions required for a valid T-test. One team will argue for the importance of each assumption, while the other will discuss potential consequences of violating these assumptions. Conclude with a class discussion on how to ensure these conditions are met in real-world scenarios.

  5. Explore Real-World Applications

    Research and present a real-world scenario where a two-sample T-test was used to make an important decision. Discuss the context, the data involved, and the outcome of the analysis. Reflect on how this relates to Kaito’s tomato plant study and the broader implications of statistical testing.

t-testA statistical test used to compare the means of two groups to determine if they are significantly different from each other. – The researcher performed a t-test to assess whether the new drug had a different effect on blood pressure compared to the placebo.

hypothesisA proposed explanation for a phenomenon, which can be tested through experimentation and observation. – The biologist formulated a hypothesis that the new fertilizer would increase plant growth rates.

significanceA statistical measure that helps to determine if the results of an experiment are likely due to chance or if they reflect a true effect. – The study’s findings were considered statistically significant, indicating a real difference between the control and experimental groups.

sampleA subset of a population selected for measurement, observation, or questioning to provide statistical information about the population. – The sample of 200 students was used to estimate the average height of the entire university student body.

statisticA numerical value that represents a property of a sample, such as the mean or standard deviation. – The statistic showed that the average test score in the class was 85, with a standard deviation of 5.

p-valueA measure that helps to determine the significance of results in hypothesis testing, indicating the probability of observing the data if the null hypothesis is true. – A p-value of less than 0.05 was obtained, suggesting that the difference in means was statistically significant.

distributionA function that shows the possible values for a variable and how often they occur, often represented as a graph or table. – The normal distribution is commonly used in statistics to model the distribution of many natural phenomena.

independenceA condition in which two or more events or variables do not influence each other. – The independence of the two genetic traits was confirmed through a chi-square test.

variationThe degree to which data points in a statistical distribution or dataset differ from the mean or from each other. – The variation in test scores was analyzed to understand the differences in student performance.

heightA measure of how tall an organism or object is, often used as a variable in biological and statistical studies. – The study examined the correlation between the height of plants and their exposure to sunlight.

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